(2x^2)/(7)+16+5x=0

Solution for (2x^2)/(7)+16+5x=0 equation:

(2x^2)/(7)+16+5x=0

We multiply all the terms by the denominator


2x^2+5x*7+16*7=0

We add all the numbers together, and all the variables

2x^2+5x*7+112=0

Wy multiply elements

2x^2+35x+112=0

a = 2; b = 35; c = +112;
Δ = b2-4ac
Δ = 352-4·2·112
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{329}}{2*2}=\frac{-35-\sqrt{329}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{329}}{2*2}=\frac{-35+\sqrt{329}}{4}
$